From 72b6014ddf2dfa770a2976102f352b630c6b90d9 Mon Sep 17 00:00:00 2001
From: smallkun <smallerkun@foxmail.com>
Date: Thu, 20 Mar 2025 11:01:11 +0800
Subject: [PATCH] 2025-03-20

---
 2207/C语言同步练习源码/7-结构体-1.c | 28 ++++++++++++++++++++++++++++
 2207/C语言同步练习答案.md           | 29 +++++++++++++++++++++++++++++
 2 files changed, 57 insertions(+)
 create mode 100644 2207/C语言同步练习源码/7-结构体-1.c

diff --git a/2207/C语言同步练习源码/7-结构体-1.c b/2207/C语言同步练习源码/7-结构体-1.c
new file mode 100644
index 0000000..1a56943
--- /dev/null
+++ b/2207/C语言同步练习源码/7-结构体-1.c
@@ -0,0 +1,28 @@
+#include <stdio.h>
+
+typedef struct student{
+    int num;
+    char name[20];
+    float socre[3];
+}student;
+//student 作为一个类型
+//如果不写typedef则结构体类型为 struct student
+
+void output(student stuList[5]){
+    int i;
+
+    for(i=0;i<5;i++){
+        printf("%d\t%s\t%f\t%f\t%f\n", stuList[i].num, stuList[i].name, stuList[i].socre[0], 
+                                stuList[i].socre[1], stuList[i].socre[2]);
+    }
+}
+int main(){
+    student stuList[5];//定义了一个结构体数组里面可以容纳5个结构体变量
+    int i;
+    for(i=0;i<5;i++){
+        scanf("%d %s %f %f %f", &stuList[i].num, stuList[i].name, &stuList[i].socre[0], 
+                                &stuList[i].socre[1], &stuList[i].socre[2]);
+    }
+    output(stuList);
+    return 0;
+}
\ No newline at end of file
diff --git a/2207/C语言同步练习答案.md b/2207/C语言同步练习答案.md
index ec6a732..c5574fa 100644
--- a/2207/C语言同步练习答案.md
+++ b/2207/C语言同步练习答案.md
@@ -935,7 +935,36 @@ int main(){
 ### 结构体-1
 
 ![image-20250227231339018](https://yp.smallkun.cn/markdown/image-20250227231339018.png!compress)
+```c
+#include <stdio.h>
 
+typedef struct student{
+    int num;
+    char name[20];
+    float socre[3];
+}student;
+//student 作为一个类型
+//如果不写typedef则结构体类型为 struct student
+
+void output(student stuList[5]){
+    int i;
+
+    for(i=0;i<5;i++){
+        printf("%d\t%s\t%f\t%f\t%f\n", stuList[i].num, stuList[i].name, stuList[i].socre[0], 
+                                stuList[i].socre[1], stuList[i].socre[2]);
+    }
+}
+int main(){
+    student stuList[5];//定义了一个结构体数组里面可以容纳5个结构体变量
+    int i;
+    for(i=0;i<5;i++){
+        scanf("%d %s %f %f %f", &stuList[i].num, stuList[i].name, &stuList[i].socre[0], 
+                                &stuList[i].socre[1], &stuList[i].socre[2]);
+    }
+    output(stuList);
+    return 0;
+}
+```
 
 
 ### 结构体-2