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smallkun 2025-03-17 19:31:35 +08:00
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2207/MySQL数据库操作综合练习题答案.md
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@ -179,6 +179,79 @@ VALUES
![image-20250315225441802](https://yp.smallkun.cn/markdown/image-20250315225441802.png!compress) ![image-20250315225441802](https://yp.smallkun.cn/markdown/image-20250315225441802.png!compress)
```sql
#5
SELECT e.empid, e.`name`, e.title, d.depname, s.basesalary + s.titleSalary, s.basesalary + s.titleSalary-IFNULL(s.decuction, 0)
FROM employee e, department d, salary s
WHERE e.depid = d.depid AND e.empid = s.empid;
#6
SELECT e.`name`, s.basesalary
FROM employee e, department d, salary s
WHERE e.depid = d.depid AND e.empid = s.empid AND d.depname = '销售部';
#7
SELECT *
FROM employee e
WHERe e.`name` LIKE '张%' AND TIMESTAMPDIFF(YEAR,e.birthday, NOW()) < 40;
#8
SELECT e.`name`, s.basesalary, s.titleSalary
FROM employee e, salary s
WHERE e.sex = '男' AND e.empid AND s.empid;
#9
SELECT e.`name`, e.title, d.depname
FROM employee e, department d, salary s
WHERE e.depid = d.depid AND e.empid = s.empid AND s.basesalary < 2000;
#10
SELECT COUNT(*)
FROM employee;
#11
SELECT COUNT(*)
FROM department d;
#12
SELECT AVG(s.basesalary + s.titleSalary), MAX(s.basesalary + s.titleSalary), MIN(s.basesalary + s.titleSalary)
FROM employee e, salary s
WHERE e.empid = s.empid;
#13
SELECT d.depname, AVG(s.basesalary + s.titleSalary)
FROM employee e, salary s, department d
WHERE e.empid = s.empid AND e.depid = d.depid
GROUP BY d.depid;
#14
SELECT d.depname, AVG(s.basesalary + s.titleSalary) avg
FROM employee e, salary s, department d
WHERE e.empid = s.empid AND e.depid = d.depid
GROUP BY d.depid
HAVING avg<2000;
#15
SELECT e.empid, e.`name`, s.basesalary, s.titleSalary, s.decuction
FROM employee e, salary s, department d
WHERE e.empid = s.empid AND e.depid = d.depid
ORDER BY s.titleSalary, s.basesalary;
#16
SELECT e.empid, e.`name`, e.birthday,
IF(YEAR(e.birthday) < 1980, '老年',
IF(YEAR(e.birthday)< 1990, '中年', '青壮年'))
FROM employee e;
#17
SELECT e.*, depname
FROM employee e, department d
WHERE e.depid = d.depid;
#18
SELECT d.*, e.*
FROM employee e, department d
WHERE e.depid = d.depid;
#19
SELECT *
FROM employee e
WHERE e.title LIKE '%工程师%' AND e.sex = '男';
#20
SELECT d.depname, e.sex, COUNT(*), AVG(s.basesalary)
FROM employee e, department d, salary s
WHERE e.depid = d.depid AND e.empid = s.empid
GROUP BY d.depid, e.sex;
```
--- ---
### 练习四 ### 练习四