2025-02-06

2025-02-06 22:43:19 +08:00
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+### 数据库
+
+```sql
+#1 创建表
+CREATE TABLE t_family(
+	fno INT(11) PRIMARY KEY AUTO_INCREMENT,
+	eno INT(11) NOT NULL COMMENT '职工编号',
+	ename VARCHAR(255) NOT NULL COMMENT '职工姓名',
+	faname VARCHAR(255),
+	moname VARCHAR(255)
+);
+
+#2 添加字段
+ALTER TABLE t_salary ADD grade VARCHAR(255) COMMENT '评级';
+
+#3 修改字段数据类型
+ALTER TABLE t_employee MODIFY sex ENUM('男', '女');
+
+#4 更新记录
+UPDATE t_department d
+SET d.tel = '128'
+WHERE d.dname = '法务部';
+
+#5 条件、排序查询
+SELECT e.ename, e.sex, e.birthday
+FROM t_employee e
+WHERE e.birthday >= '2000-1-1'
+ORDER BY e.birthday DESC;
+
+#6 分组、多表连接查询
+SELECT d.dname, SUM(s.basepay+s.overtime+s.allowance+s.insurance)
+FROM t_department d, t_employee e, t_salary s
+WHERE e.dno = d.dno AND e.eno = s.eno
+GROUP BY d.dno;
+#7 分组+排序 视图
+CREATE VIEW v_jobcount AS
+SELECT j.jobtitle, COUNT(*)
+FROM t_job j, t_employee e
+WHERE j.jno  = e.jobno
+GROUP BY j.jno
+ORDER BY 2;
+
+#8 触发器
+CREATE TRIGGER  tri_updateGrade
+BEFORE UPDATE ON t_salary FOR EACH ROW
+BEGIN
+	IF	NEW.basepay < 6000 THEN
+			SET NEW.grade = 'C';
+	ELSEIF NEW.basepay < 8000 THEN 
+			SET NEW.grade = 'B'; 
+	ELSEIF NEW.basepay >= 8000 THEN
+			SET NEW.grade = 'A';
+	END IF;
+END;
+#9 存储过程
+CREATE  PROCEDURE `pro_getDepartmentTel`(in `in_dno` int, OUT dept_phone VARCHAR(100)) 
+	BEGIN
+
+		SELECT CONCAT('部门名称-', dname, '，电话-', tel) INTO dept_phone
+		FROM t_department
+		WHERE dno =  `in_dno` limit 1;
+			
+		IF dept_phone IS NULL THEN
+        			SET dept_phone = '没有找到相应的部门';
+		END IF;
+	END
+```
+
+### C语言-1
+
+```c
+/*---------------------------------------------------------
+【程序设计】输入n个整数，以-1结束，求所输入的整数中，十位是奇数的所有整数之和。
+例1：
+输入n个整数，求十位为奇数的数之和（输入-1结束）:
+10 15 20 25 30 40 50 -1
+十位为奇数的数之和为: 105
+例2：
+输入n个整数，求十位为奇数的数之和（输入-1结束）:
+8 18 28 -38 48 58 -1 98
+十位为奇数的数之和为: 38
+------------------------------------------------------------------------
+注意：部分源程序给出如下。请勿改动主函数main或其它函数中给出的内容，仅在
+Program-End之间填入若干语句。不要删除标志否则不得分。
+---------------------------------------------------------*/
+#include <stdio.h>
+int main() {
+	int num,tenDigit;
+	int sum = 0,i;
+	printf("输入n个整数，求十位为奇数的数之和（输入-1结束）:\n");
+	while (1) 
+	{
+		scanf("%d", &num);
+		/**********Program**********/ 
+		if(num == -1){
+			break;
+		}
+		if((num<0?num*-1:num)%100/10%2==1){
+			sum += num;
+		}
+
+
+
+
+	/**********  End  **********/
+	}
+	printf("十位为奇数的数之和为: %d\n", sum);
+}
+```
+