2208/天天乐学考试答案/MySQL练习（一）.md

@@ -243,21 +243,7 @@ WHERE b.note = a.author_name
 GROUP BY a.author_id
 HAVING COUNT(*) > 1;
 
-#9 视图
-CREATE VIEW v_book AS
-SELECT b.genre, a.author_name, COUNT(*) c
-FROM tb_books b, tb_authors a
-WHERE b.note = a.author_name
-GROUP BY b.genre, a.author_id 
-HAVING COUNT(*) = ( #子查询用来统计这个类别中 数量最多的作者的图书数量
-	SELECT COUNT(*)
-	FROM tb_books
-	WHERE b.genre = genre
-	GROUP BY note
-	ORDER BY COUNT(*) DESC
-	LIMIT 1
-);
-
 
+#9
 ```