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2207/C语言同步练习源码/4.函数-3.c

@@ -0,0 +1,30 @@
+#include <stdio.h>
+
+//Ãݴη½ 
+int power(int n){
+	int s = 1, i;
+	for(i=1;i<=n;i++){
+		s *= 2;
+	}
+	return s;
+}
+//½×³Ë 
+int factorial(int n){
+	int s = 1, i;
+	for(i=1;i<=n;i++){//1~n
+		s*=i;
+	}
+	return s;
+}
+
+int main(){
+	int n, i, s = 0;
+	scanf("%d", &n);
+	for(i=1;i<=n;i++){
+		s += power(i) * factorial(i);
+	}
+	printf("%d\n", s);
+
+	return 0;
+}
+

2207/C语言同步练习答案.md

@@ -702,6 +702,36 @@ int main(){
 ![image-20250227231154429](https://yp.smallkun.cn/markdown/image-20250227231154429.png!compress)
 
 ```c
+#include <stdio.h>
+
+//幂次方 
+int power(int n){
+	int s = 1, i;
+	for(i=1;i<=n;i++){
+		s *= 2;
+	}
+	return s;
+}
+//阶乘 
+int factorial(int n){
+	int s = 1, i;
+	for(i=1;i<=n;i++){//1~n
+		s*=i;
+	}
+	return s;
+}
+
+int main(){
+	int n, i, s = 0;
+	scanf("%d", &n);
+	for(i=1;i<=n;i++){
+		s += power(i) * factorial(i);
+	}
+	printf("%d\n", s);
+
+	return 0;
+}
+
 ```