5.8 KiB
5.8 KiB
C语言-1
/*------------------------------------------------------------------------------
（1）【程序设计】下列给定程序中，fun函数的功能是：分别统计字符串中大写字母和小写字母的个数。
例如，给字符串s输入：AAaaBBbb123CCcccd，则应输出：upper＝6，lower＝8。
------------------------------------------------------------------------------*/
#include <stdio.h>
void fun ( char *s, int *a, int *b)
{
/**********Program**********/
while(*s != '\0'){
if(*s >= 'A' && *s <= 'Z'){
(*a)++;
}
if(*s >= 'a' && *s <= 'z'){
(*b)++;
}
s++;
}
/********** End **********/
}
main( )
{
char s[100];
int upper=0, lower=0;
printf( "\nPlease a string : " );
gets(s);
fun(s,&upper,&lower);
printf("\n upper=%d lower=%d\n",upper,lower );
}
C语言-2
/*------------------------------------------------------------------------
题目：函数fun的功能：将字符串str中第k个字符开始的n个字符逆序重排，
例如：输入1,5 输出54321abcde
输入3,6 输出12cba543de
注意：部分源程序给出如下。请勿改动主函数main或其它函数中给出的内容，仅在
Program-End之间填入若干语句。不要删除标志否则不得分。
----------------------------------------------------------------------*/
#include <stdio.h>
#include <string.h>
void fun(char *str, int k, int n )
{
int i,j; char t;
for(i=k-1,j=k-1+n-1;i<j;i++,j--)
{
/**********Program**********/
t = str[i];
str[i] = str[j];
str[j] = t;
/********** End **********/
}
}
int main( )
{
char str[]="12345abcde";
unsigned int k,n;
scanf("%d,%d",&k,&n);
if(k+n-1<=strlen(str))
{ fun(str,k,n);
puts(str); }
else
printf("所输入的k,n值不合适！\n");
return 0;
}
C语言-3
/*------------------------------------------------------------------
功能：编程统计一个字符串中的字母、数字、空格和其它字符的个数。
---------------------------------------------------------------------*/
#include <stdio.h>
void fun(char s[],int b[])
{
int i;
/**********Program**********/
i=0;
while(s[i] != '\0'){
if(s[i] >= 'a' && s[i] <= 'z' || s[i] >= 'A' && s[i] <= 'Z'){
b[0]++;
}else if(s[i] >= '0' && s[i] <= '9'){
b[1]++;
}else if(s[i] == ' '){
b[2]++;
}else{
b[3]++;
}
i++;
}
/********** End **********/
}
main ()
{
char s1[80];int a[4]={0};
int k;
void fun(char s[],int b[]) ;
gets(s1);
fun(s1,a);
puts(s1);
for(k=0;k<4;k++)
printf("%4d",a[k]);
}
C语言-4
/*------------------------------------------------------------------------
程序功能：从键盘输入三个整数，比较三个数并显示相应信息，具体如下：
（1）如果三个数都相等，显示"***"；
（2）如果三个数中只有某两个数相等，显示"@@"；
（3）如果三个数互不相等，则显示"&"。
（输出要换行）
------------------------------------------------------------------------
注意：部分源程序给出如下。请勿改动主函数main或其它函数中给出的内容，仅在
Program-End之间删除【?】填入若干语句。不要删除标志否则不得分。
----------------------------------------------------------------------*/
#include<stdio.h>
int main()
{
int a,b,c;
scanf("%d%d%d",&a,&b,&c);
if(a==b && b==c)
printf("***\n");
/**********Program**********/
else if(a==b || b==c || a==c)
/********** End **********/
printf("@@\n");
else printf("&\n");
return 0;
}
MySQL-1
#1
CREATE TABLE t_hotel_manager(
mid INT PRIMARY KEY,
hid INT NOT NULL,
mname VARCHAR(10) NOT NULL,
mage INT NOT NULL,
mgender ENUM('男', '女', '未知'),
telephone VARCHAR(11)
);
#2
#使用MODIFY添加主键字段为自动增长
ALTER TABLE t_hotel_manager MODIFY mid INT AUTO_INCREMENT;
#设置自增起始值
ALTER TABLE t_hotel_manager AUTO_INCREMENT = 1000;
#3
INSERT INTO t_hotel_manager()
VALUES(DEFAULT, 10001, '王璐', 32, '女', NULL);
#4
CREATE TABLE t_hotel_bak AS
SELECT *
FROM t_hotel;
#5
UPDATE t_client c
SET c.integral = c.integral + 100
WHERE c.cname LIKE '姚%';
#6 tj11
SELECT c.cname, SUM(r.price)
FROM t_booking b, t_client c, t_room r
WHERE b.cid = c.cid AND b.rid = r.rid
GROUP BY c.cid
ORDER BY 2 DESC
LIMIT 9, 1;
#7 tj12
SELECT h.hname, r.price
FROM t_hotel h, t_room r
WHERE h.hid = r.hid AND r.rname = '大床房' AND r.price = (
SELECT MAX(price)
FROM t_room
WHERE rname = '大床房'
);
#8 tj13
SELECT h.hname, r.rname, r.price
FROM t_room r
LEFT JOIN t_booking b ON r.rid = b.rid
INNER JOIN t_hotel h ON r.hid = h.hid
WHERE b.bid IS NULL;
#9 视图
CREATE VIEW v_tongji AS
SELECT h.hname, SUM(r.price)
FROM t_hotel h, t_booking b, t_room r
WHERE h.hid = r.hid AND b.rid = r.rid
GROUP BY h.hid;
MySQL-2
#1添加主键
ALTER TABLE tb_student ADD PRIMARY KEY(student_id);
#2设置默认值
ALTER TABLE tb_student ALTER gender SET DEFAULT '男';
#3 插入记录
INSERT INTO tb_student()
VALUES(10025, '张三', DEFAULT, '2012-10-01', 1001);
#4 更新记录
UPDATE tb_teacher t
SET t.teacher_age = 36
WHERE t.teacher_name = '王老师';
#5 tj11
SELECT MAX(t.teacher_age)
FROM tb_teacher t;
#6 tj12
SELECT c.class_name, s.student_name, s.gender
FROM tb_teacher t, tb_student s, tb_class C
where s.class_id = c.class_id AND c.teacher_id = t.teacher_id;
#7 视图
CREATE VIEW v_teacher AS
SELECT c.class_name, t.teacher_name, COUNT(*)
FROM tb_teacher t, tb_student s, tb_class C
WHERE s.class_id = c.class_id AND c.teacher_id = t.teacher_id
GROUP BY c.class_id, t.teacher_name;
#8
DELIMITER $$
DROP TRIGGER IF EXISTS tri_updateTeacherAge;
CREATE TRIGGER tri_updateTeacherAge
BEFORE UPDATE ON tb_teacher
FOR EACH ROW
BEGIN
IF NEW.teacher_age < 30 THEN
SET NEW.age = '青年';
ELSEIF NEW.teacher_age < 50 THEN
SET NEW.age = '中年';
ELSE
SET NEW.age = '老年';
END IF;
END $$
DELIMITER ;
#9
DELIMITER $$
DROP PROCEDURE IF EXISTS Pro_GetOldClassStudent;
CREATE PROCEDURE Pro_GetOldClassStudent(IN in_class_id INT, OUT out_student_name VARCHAR(50))
BEGIN
SELECT s.student_name INTO out_student_name
FROM tb_student s, tb_class c
WHERE s.class_id = c.class_id AND c.class_id = in_class_id
ORDER BY s.birthday
LIMIT 1;
END $$
DELIMITER ;
CALL Pro_GetOldClassStudent(1001, @result);
SELECT @result;