111 lines
2.7 KiB
Markdown
111 lines
2.7 KiB
Markdown
### 数据库
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```sql
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#1 创建表
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CREATE TABLE t_family(
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fno INT(11) PRIMARY KEY AUTO_INCREMENT,
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eno INT(11) NOT NULL COMMENT '职工编号',
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ename VARCHAR(255) NOT NULL COMMENT '职工姓名',
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faname VARCHAR(255),
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moname VARCHAR(255)
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);
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#2 添加字段
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ALTER TABLE t_salary ADD grade VARCHAR(255) COMMENT '评级';
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#3 修改字段数据类型
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ALTER TABLE t_employee MODIFY sex ENUM('男', '女');
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#4 更新记录
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UPDATE t_department d
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SET d.tel = '128'
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WHERE d.dname = '法务部';
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#5 条件、排序查询
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SELECT e.ename, e.sex, e.birthday
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FROM t_employee e
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WHERE e.birthday >= '2000-1-1'
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ORDER BY e.birthday DESC;
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#6 分组、多表连接查询
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SELECT d.dname, SUM(s.basepay+s.overtime+s.allowance+s.insurance)
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FROM t_department d, t_employee e, t_salary s
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WHERE e.dno = d.dno AND e.eno = s.eno
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GROUP BY d.dno;
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#7 分组+排序 视图
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CREATE VIEW v_jobcount AS
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SELECT j.jobtitle, COUNT(*)
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FROM t_job j, t_employee e
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WHERE j.jno = e.jobno
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GROUP BY j.jno
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ORDER BY 2;
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#8 触发器
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CREATE TRIGGER tri_updateGrade
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BEFORE UPDATE ON t_salary FOR EACH ROW
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BEGIN
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IF NEW.basepay < 6000 THEN
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SET NEW.grade = 'C';
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ELSEIF NEW.basepay < 8000 THEN
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SET NEW.grade = 'B';
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ELSEIF NEW.basepay >= 8000 THEN
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SET NEW.grade = 'A';
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END IF;
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END;
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#9 存储过程
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CREATE PROCEDURE `pro_getDepartmentTel`(in `in_dno` int, OUT dept_phone VARCHAR(100))
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BEGIN
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SELECT CONCAT('部门名称-', dname, '，电话-', tel) INTO dept_phone
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FROM t_department
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WHERE dno = `in_dno` limit 1;
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IF dept_phone IS NULL THEN
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SET dept_phone = '没有找到相应的部门';
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END IF;
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END
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```
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### C语言-1
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```c
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/*---------------------------------------------------------
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【程序设计】输入n个整数，以-1结束，求所输入的整数中，十位是奇数的所有整数之和。
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例1：
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输入n个整数，求十位为奇数的数之和（输入-1结束）:
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10 15 20 25 30 40 50 -1
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十位为奇数的数之和为: 105
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例2：
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输入n个整数，求十位为奇数的数之和（输入-1结束）:
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8 18 28 -38 48 58 -1 98
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十位为奇数的数之和为: 38
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------------------------------------------------------------------------
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注意：部分源程序给出如下。请勿改动主函数main或其它函数中给出的内容，仅在
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Program-End之间填入若干语句。不要删除标志否则不得分。
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---------------------------------------------------------*/
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#include <stdio.h>
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int main() {
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int num,tenDigit;
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int sum = 0,i;
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printf("输入n个整数，求十位为奇数的数之和（输入-1结束）:\n");
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while (1)
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{
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scanf("%d", &num);
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/**********Program**********/
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if(num == -1){
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break;
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}
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if((num<0?num*-1:num)%100/10%2==1){
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sum += num;
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}
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/********** End **********/
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}
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printf("十位为奇数的数之和为: %d\n", sum);
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}
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```
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