88 lines
2.2 KiB
Markdown
88 lines
2.2 KiB
Markdown
### 作业1
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| 薪水 | 涨薪幅度 |
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| --------------- | -------- |
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| 0-400.00 | 15% |
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| 400.01-800.00 | 12% |
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| 800.01-1200.00 | 10% |
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| 1200.01-2000.00 | 7% |
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| 超过 2000.00 | 4% |
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读取员工的工资，计算并输出员工的新工资，以及员工增加的收入和涨薪幅度。
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```c
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#include <stdio.h>
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int main() {
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double money;
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scanf("%lf", &money);
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if (0 < money && money <= 400) {
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printf("涨工资后，工资为：%lf\n", money * 1.15);
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printf("涨工资幅度是15%%\n");
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printf("涨了%lf元工资\n", money * 0.15);
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}
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if (400 < money && money <= 800) {
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printf("涨工资后，工资为：%lf\n", money * 1.12);
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printf("涨工资幅度是12%%\n");
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printf("涨了%lf元工资\n", money * 0.12);
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}
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if (800 < money && money <= 1200) {
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printf("涨工资后，工资为：%lf\n", money * 1.1);
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printf("涨工资幅度是10%%\n");
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printf("涨了%lf元工资\n", money * 0.1);
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}
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if (1200 < money && money <= 2000) {
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printf("涨工资后，工资为：%lf\n", money * 1.07);
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printf("涨工资幅度是7%%\n");
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printf("涨了%lf元工资\n", money * 0.07);
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}
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if (2000 < money) {
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printf("涨工资后，工资为：%lf\n", money * 1.04);
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printf("涨工资幅度是4%%\n");
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printf("涨了%lf元工资\n", money * 0.04);
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}
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return 0;
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}
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```
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### 作业2
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```
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零食种类 价格
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零食 1 R$ 4.00
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零食 2 R$ 4.50
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零食 3 R$ 5.00
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零食 4 R$ 2.00
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零食 5 R$ 1.50
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```
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现在给定某种零食的编号和数量，请你计算总价值是多少。
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输入包含两个整数 x 和 y，其中 x 为零食编号，y 为零食数量。
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```c
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#include <stdio.h>
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int main() {
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int x, y;
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scanf("%d%d", &x, &y);
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if (x == 1) {
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printf("Total: R$ %.2lf", 4.0 * y);
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}
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if (x == 2) {
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printf("Total: R$ %.2lf", 4.5 * y);
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}
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if (x == 3) {
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printf("Total: R$ %.2lf", 5.0 * y);
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}
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if (x == 4) {
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printf("Total: R$ %.2lf", 2.0 * y);
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}
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if (x == 5) {
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printf("Total: R$ %.2lf", 1.5 * y);
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}
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return 0;
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}
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```
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